(1)x^2+x-6=0(x+3)(x-2)=0所以x=-3或x=2(2)x^2-2011x-2012=0(x+1)(x-2012)=0所以x=-1或x=2012
:(1) x^2+x-6=0﹙x-2﹚﹙x+3﹚=0x-2=0, x+3=0x=2, x=-3x^2-2011x-2012=0﹙x-2012﹚﹙x+1﹚=0x-2012=0, x+1=0x=2012, x=-1
1.(x+3)(x-2)=02.(x-2012)(x+1)=0