已知x2-xy=5,xy-y2=-3,求代数式x2-y2和x2-2xy+y2的值。这样。

2024-12-17 17:41:29
推荐回答(4个)
回答1:

x2-y2
=x2-xy+xy-y2
=5-3
=2

x2-2xy+y2
=x2-xy-(xy-y2)
=5-(-3)
=8

回答2:

x2-y2
=x²-xy+xy-y²
=5-3
=2

x2-2xy+y2
=x²-xy-xy+y²
=x²-xy-(xy-y²)
=5+3
=8

回答3:

x2-y2=2
x2-2xy+y2=8

回答4:

x2-y2=2 x2-2xy+y2=8