x²-x+1=(x-1/2)²+3/4 值域是大于等于3/4∴1/(x²-x+1) 的值域是(0,4/3]y=2x2-2x+3/x2-x+1=2+1/(x²-x+1) ∴值域是(2,10/3]
y=2(x2-x+1)+1/x2-x+1 =2+1/x2-x+1设f(x)=x2-x+1对称轴为x=1/2fmin=3/4ymax=10/3所以值域为(2,10/3】