1⼀4-x+1⼀(X-1)(x-2)+1⼀(x-2)(x-3)+1⼀(X-3)(x-4)怎样计算

2024-12-12 01:34:25
推荐回答(2个)
回答1:

1/(X-1)(x-2)=1/(x-2)-1/(x-1)所以1/(4-x)+1/(X-1)(x-2)+1/(x-2)(x-3)+1/(X-3)(x-4)=1/4-x+1/(x-2)-1/(x-1)+1/(x-3)-1/(x-2)+1/(x-4)-1/(x-3)=-1/(x-1)

回答2:

1/4-x+1/(X-1)(x-2)+1/(x-2)(x-3)+1/(X-3)(x-4)
=-1/(x-4)+1/(x-2)-1/(x-1)+1/(x-3)-1/(x-2)+1/(x-4)-1/(x-3)
=-1/(x-1)