1/(x-1)=4/(x²-1)两边乘以(x+1)(x-1)，得x+1=4x=3经检验x=3是方程的解∴方程的解是x=3
1/（x-1）=4/(x^2-1)1/（x-1）-4/[(x-1)(x+1)]=0(x+1-4)/[(x-1)(x+1)]=0(x-3)/[(x-1)(x+1)]=0x=3
一分之4是4吗
