(1-1⼀2^2)(1-1⼀3^2)(1-1⼀4^2)……(1-1⼀2009^2)=?

2024-12-19 02:21:11
推荐回答(2个)
回答1:

(1-1/2^2)(1-1/3^2)(1-1/4^2)……(1-1/2008^2)(1-1/2009^2)
=(1-1/2)(1+1/2)(1-1/3)(1+1/3)(1-1/4)(1+1/4).……(1-1/2008)(1+1/2008)(1-1/2009)(1+1/2009)
=1/2 * 3/2 * 2/3 * 4/3 * 5/4……2007/2008 * 2008/2009 * 2010/2009
=1/2 * 2010/2009
=1005/2009

回答2:

解:原式=(1-1/2)(1+1/2)(1-1/3)(1+1/3)(1-1/4)(1+1/4)···(1-1/2009)(1+1/2009)
=1/2·3/2·2/3·4/3·3/4·5/4···2008/2009·2010/2009
=1/2·2010/2009
=1005/2009