求方程组x+y⼀2+x-y⼀3=1,4(x+y)-5(x-y)=2的值

2024-12-21 19:18:55
推荐回答(2个)
回答1:

(x+y)/2+(x-y)/3=1 ====>1式
4(x+y)-5(x-y)=2 ===>2式
1式乘以24 ===>12(x+y)+8(x-y)=24
2式乘以3 ===>12(x+y)-15(x-y)=6
解得
x+y=34/23
x-y=18/23

x=26/23
y=8/23

回答2:

x=52/109,y=30/109