2xy-x눀-y눀+1分解因式

2024-12-29 04:48:28
推荐回答(3个)
回答1:

琉璃苣的夏天,你好!
解:2xy-x²-y²+1
=1-(x²-2xy+y²)
=1-(x-y)²
=(1-x+y)(1+x-y)

回答2:

2xy-x²-y²+1
=1-(x²+y²-2xy)
=1-(x-y)²
=(1+x-y)(1-x+y)

回答3:

(xy-1)的平方