x/(x-3)-3x/(x^2-3x)-3/x=x^2/(x^2-3x)-3x/(x^2-3x)-3(x-3)/(x^2-3x)=[x^2-3x-3(x-3)](x^2-3x)=[x^2-3x-3x+9]/(x^2-3x)=(x^2-6x+9)/(x^2-3x)=(x-3)^2/[x(x-3)]=(x-3)/x=(3/2-3)/(3/2)=-(3/2)/(3/2)=-1
