通过点M(2,1,3) 且与直线L:(x+1)⼀3=(y-1)⼀2=z⼀-1垂直相交的直线方程是? 程过求

2024-12-14 10:44:51
推荐回答(1个)
回答1:

(x+1)/3=(y-1)/2
2x+2=3y-3
y=2x/3+5/3
过M垂直y=2x/3+5/3 y-1=-1/(2/3) (x-2)
y=4-3x/2
(x+1)/3=z/-1
3z=-x-1,z=-x/3-1/3
过M垂直z=-x/3-1/3 z-3=-1/(-1/3) (x-2)
z=3x-3
过M垂直直线L:
(4-y)+(z+3)/2=3x
8-2y+z+3=6x
x+2y-z-11=0