如图,已知△ABC中,∠B=45° ∠C=30°,AB=根号2,求AC的长

2025-01-02 05:14:28
推荐回答(2个)
回答1:

AC/sinB=AB/sinC
AC=sinB*AB/sinC
=√2/2 * √2 / 1/2
=2
所以AC的长为2

回答2:

AC/sinB=AB/sinC
AC=sinB*AB/sinC
=√2/2 * √2 / 1/2
=2