y=(t+1)sin눀3t,求导

2024-11-25 19:16:45
推荐回答(1个)
回答1:

y=(t+1)sin²3t
那么求导得到
y'=(t+1)'*sin²3t+(t+1)*(sin²3t)'
=sin²3t+(t+1)*2sin3t*(sin3t)'
=sin²3t+6(t+1)*sin6t