用初等变换求逆矩阵： 设A =3 -2 0 -1 0 2 2 1 1 -2 -3 -2 0 1 2 1 谢谢啊，快快···

呵呵 来晚了
解: (A,E) =
3 -2 0 -1 1 0 0 0
0 2 2 1 0 1 0 0
1 -2 -3 -2 0 0 1 0
0 1 2 1 0 0 0 1

r1-3r3 (第1行减3倍的第3行)
0 4 9 5 1 0 -3 0
0 2 2 1 0 1 0 0
1 -2 -3 -2 0 0 1 0
0 1 2 1 0 0 0 1

r1-4r4, r2-2r4, r3+2r4
0 0 1 1 1 0 -3 -4
0 0 -2 -1 0 1 0 -2
1 0 1 0 0 0 1 2
0 1 2 1 0 0 0 1

r2+2r1, r3-r1, r4-2r1
0 0 1 1 1 0 -3 -4
0 0 0 1 2 1 -6 -10
1 0 0 -1 -1 0 4 6
0 1 0 -1 -2 0 6 9

r1-r2, r3+r2, r4+r2
0 0 1 0 -1 -1 3 6
0 0 0 1 2 1 -6 -10
1 0 0 0 1 1 -2 -4
0 1 0 0 0 1 0 -1

交换行得
1 0 0 0 1 1 -2 -4
0 1 0 0 0 1 0 -1
0 0 1 0 -1 -1 3 6
0 0 0 1 2 1 -6 -10

满意请采纳 ^-^.

1 0 0 0 1 1 -2 -4
0 1 0 0 0 1 0 -1
0 0 1 0 -1 -1 3 6
0 0 0 1 2 1 -6 -10