x²-1分之2减去x-1分之1等于1
两边同乘以(x+1)(x-1)得
2-(x+1)=x^2-1
x^2+x-2=0 (x+2)(x-1)=0 x1=-2 x2=1(是增根)
∴方程的解为x=-2
(2/x²-1)-(1/x-1)=1
(2/x²-1)-(x+1/x²-1)=1
2-x-1/x²-1=1
1-x/(x-1)(x+1)=1
-(x+1)=1
x=-2
understand?
解(2-X-1)/(X+1)(X-1)=1
1-X=(X+1)(X-1)
X=1或-2
舍去1(分母不为0)
所以X=-2
2/(x²-1)-1/(x-1)=1
2/(x²-1)-(x+1)/(x²-1)=1
(2-x-1)/(x²-1)=1
1-x=x²-1
-(x-1)=(x-1)(x+1)
-1=x+1
x=-2
-2