(2x-1)²+(1-2x)-6= (1-2x)²+(1-2x)-6=0,令1-2x=y,则y²+y-6=(y-2)(y+3)=0,y=2或y=-3,
所以x=-1/2或x=2.
√2(x-1)²=(1-x) 所以√2(1-x)²-(1-x)=0,令1-x=y,则√2y²-y= y(√2y-1)=0,y=0或y=√2/2
所以x=1或x=1-√2/2.
(2x-1)²-(2x-1)-6=0
(2x-1-3)(2x-1+2)=0
2(x-2)(2x+1)=0
x=2,x=-1/2
√2(x-1)²+(x-1)=0
(x-1)(√2x-√2+1)=0
x=1,x=(2-√2)/2