你的题目打错了,应该是:1/(x²-1)-2/(x+1)-1/(x-1)=01/[(x+)(x-1)]-2/(x+1)-1/(x-1)=01-2(x-1)-(x+1)=01-2x+2-x-1=03x=2x=2/3经检验,x=2/3是原方程的根