解:[2+(2^0)+(2^-1)]/[(2^-2)(2^-3)(2^-4)] =[2+1+(1/2)]÷[(1/4)×(1/8)×(1/16)] =7/2÷(1/512)=1792
1792
原式=(2+1+1/2)/(1/4*1/8*1/16)=(7/2)/(1/152)=1 792
=(2+1+1/2)/2^(-2-3-4)=(7/2)/(2^-9)=7/2×2^9=7×256=1792