﹙9又2/7+7又2/9﹚÷﹙5/7+5/9﹚=﹙65/7+65/9﹚÷﹙5/7+5/9﹚=65×﹙1/7+1/9﹚÷[5×﹙1/7+1/9﹚]=65×﹙1/7+1/9﹚÷5÷﹙1/7+1/9﹚=65÷5×[﹙1/7+1/9﹚÷﹙1/7+1/9﹚]=13×1=13
(9又7分之2+7又9分之2)除以(7分之5+9分之5)的简…2997