急!跪求各位大神请帮忙解一下这道高三数学题,步骤详细点,谢谢了!

2024-12-29 12:29:57
推荐回答(1个)
回答1:

sinA(cosB+cosC)=sinB+sinC

sinA=sinB+sinC/cosB+cosC
sinA=tan(B+C)/2
2sin(B+C)cos(B+C)=tan(B+C)/2
2cos(B+C)=1/cos(B+C)
B+C=45
A=90