y=1/(1-x^2)1-x^2=1/yx^2=1-1/y=(y-1)/yx=√[y(y-1)]/y 或 x=-√[y(y-1)]/y所以1/(1-x^2)的原函数是√[x(x-1)/x 或-√[x(x-1)/x
arcsin(x) + C
