原式=4²(x-1)²-(x+2)²
=[4(x-1)]²-(x+2)²
=[4(x-1)+(x+2)][4(x-1)-(x+2)]
=(4x-4+x+2)(4x-4-x-2)
=(5x-2)(3x-6)
=3(5x-2)(x-2)
原式=[4(x-1)-(x-2)][4(x-1)+(x-2)]=(3x-6)(5x-2)
16（x-1）²-（x+2）²
=（4x-4）^2-（x+2）²
=(3x-6)(5x-2)
16（x-1）²-（x+2）²
=[4（x-1）]²-(x+2）²
=[4（x-1）+(x+2)][4（x-1）-(x+2)]
=(5x-2)(3x-6)
16（x-1）²-（x+2）²
=(4x-4+x+2)(4x-4-x-2)
=(5x-2)(3x-6)
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