球一道物理题???

2024-12-21 19:53:06
推荐回答(2个)
回答1:

125cm^3=0.000125m^3
m=600kg/m^3×0.000125m^3=0.075kg
G物=mg=0.075kg×10N/kg=0.75N
漂浮:F浮=G物=0.75N V排= (0.000125m^3)/2=0.0000625m^3
F浮=盐水密度×g×V排=0.75N
盐水密度=1200kg/m^3

回答2:

65855+85998