1.
The time he used for his first journey: 60 miles /60 mph = 1 hour
The time he used for his second journey: 60 miles / 75 mph = 0.8 hour
the average speed:
v = (60 miles + 60 miles) / (1 hour + 0.8 hour)=120 miles / 1.8 hours = 200/3 mph ≈ 66.7 mph
希望回答对你有帮助
1。驾驶时沿固定每小时60(英里)的第一英里60英里,在一个恒定的最后75英里60英里的高速公路,埃德驱动器。什么是埃德的平均时速在他的旅程?提示:答案是不是60和七五英里每小时的平均水平。
1) find out the total time cost, which equals the time spend in first 60 miles plus time spend in final 60 miles, the time duriation will be T= 60 miles / (60mph) + 60 miles / (75mph) = 1.8hrs
2) the total displacement equals first 60 miles + final 60 miles = 120 miles.
3) Average speed = total displacement / total time cost = 120 miles / 1.8hrs = 66.7mph
这是物理题么?这不是数学题么
(60 + 60) ÷ (60 ÷ 60 + 60 ÷ 75) ≈ 66.67
英文答案是神马意思,英文数字么?
(花在前60英里的时间)the time spent on the first 60 miles :60miles/60mph=1hour
(花在后60英里的时间)the time spent on the final 60 miles:60miles/75mph=0.8hour
(平均速度=路程/时间)the average speed on his journey:(60+60)miles/1.8hour=66.67mph