f(x)=x-1⼀x^2-1的间断点

2024-12-16 00:35:30
推荐回答(2个)
回答1:

f(x) = [ |x|(x-1) ] / [x*(x^2-1) ]
= [ |x|(x-1) ] / [x*(x+1)(x-1) ]
= |x| / [x*(x+1)]

x*(x+1)(x-1)≠0
x≠0;x≠-1;x≠1

间断点:x=0;x=-1;x=1
其中:
x=0,不可去间断点;
x=-1不可去间断点;
x=1可去间断点

回答2:

无穷间断点x=0