sin2x的n阶导数怎么求

2024-12-18 22:30:27
推荐回答(2个)
回答1:

若n除以4余1,sin2x的n阶导数为2^n ·cos2x
若n除以4余2,sin2x的n阶导数为-2^n ·sin2x
若n除以4余3,sin2x的n阶导数为-2^n ·cos2x
若n能被4整除,sin2x的n阶导数为2^n ·sin2x
综合起来,sin2x的n阶导数为:2^nsin(2x+nπ/2)

回答2:

y=sin2x
y'=2cos2x=2sin(2x+π/2)
y"=-4sin2x=4sin(2x+π)
y"'=-8cos2x=8sin(2x+3π/2)
y""=16sin2x=16sin(2x+2π)
.....
y^(n)=2^nsin(2x+nπ/2)