(2x+y)^2-(x+2y)^2 =(2x+y-x-2y)(2x+y+x+2y)=(x-y)(3x+3y)=3(x-y)(x+y)
平方差原式=[(2x+y)+(x+2y)][(2x+y)-(x+2y)]=(3x+3y)(x-y)=3(x+y)(x-y)
(2x+y)^2-(x+2y)^2 =4x^2+y^2+4xy-x^2-4y^2-4xy=3x^2-3y^2=3(x+y)(x-y)
3(x^2-y^2)