|求高阶导数| y=(1-x)⼀(1+x) 求y^(n)?

2024-12-14 06:38:18
推荐回答(2个)
回答1:

y = (1-x)/(1+x) = (2-1-x)/(1+x) = 2/(1+x) - 1
y' = 2(-1)/(1+x)^2
y'' = 2(-1)(-2)/(1+x)^3
......................................
y^(n) = 2(-1)^n n!/(1+x)^(n+1)

回答2: