2mx²-x²+5x+8-(7x²-3y+5x)
=2mx²-x²+5x+8-7x²+3y-5x
=(2m-1-7)x²+3y+8
与x无关则x²系数为0
所以2m-1-7=0
m=4
所以m²-【2m²-(5m-4)+m】
=m²-2m²+5m-4-m
=-m²+4m-4
=-16+16-4
=-4
若2m乘x的2次方-x的2次方+5x+8-(7乘x的2次方-3y+5x)的值与x无关
可知所有关于x的项将全部抵消,所以m=4
m^2-[2m^2-5m+4+m]=-m^2+4m-4=-16+16-4=-4
2mx^2-x^2+5x+8-(7x^2-3y+5x)
=(2m-8)x^2+3y+8的值与x无关
2m-8=0
m=4
m^2-[2m^2-(5m-4)+m]
=m^2-2m^2+5m-4-m
=-m^2+4m-4
=-(m-2)^2
=-(4-2)^2
=-4