设BE与AC的交点是O∠AOC与∠EOC是察神对顶角∴∠AOC=∠EOC又平行四边枣迅形ABCD，AB∥CD∠BAC=∠ACD,∴△ABO∽△CEO又∵凳没此E是CD中点∴AB=2CE∴BO=2OEAO=2OC(同高，底BO=2OE)∴四边形面积=2△ABC面积=12△OCE面积=96
