一道高一数学问题

2024-12-22 19:22:57
推荐回答(2个)
回答1:

如图所示,图片需要审核,稍等

回答2:

a = 1/(2+√3) = 2-√3
b = 1/(2-√3) = 2+√3

a+1 = 3-√3
1/(a+1) = 1/(3-√3) = (3+√3)/6
b+1 = 3+√3
1/(b+1) = (3-√3)/6

1/(a+1)² + 1/(b+1)²
= [(3+√3)²+(3-√3)²] / 6²
= 2×(3²+(√3)²) / 36
= 2/3