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230问答网 > 完全燃烧一定质量的无谁乙醇，放出的热量为Q，已知为了完全吸收生成的二氧化碳，消耗掉8mol⼀l

完全燃烧一定质量的无谁乙醇，放出的热量为Q，已知为了完全吸收生成的二氧化碳，消耗掉8mol⼀l

2025-03-29 11:24:46

推荐回答（1个）

回答1：

n(NaOH)=V`c=0.4 mol
若未发生Na2CO3+CO2+H2O=2NaHCO3
2NaOH+CO2=Na2CO3+H20
n(CO2)=0.2 mol
C2H50H+3O2=2CO2+3H20
n(C2H5OH)=0.1 mol
当n(C2H5OH)=1 mol时，放出10Q热量。
若发生Na2CO3+CO2+H2O=2NaHCO3
2NaOH+ CO2= Na2CO3+H20
0.4mol 0.2mol 0.2mol
Na2CO3+CO2+ H2O=2NaHCO3
0.2mol 0.2mol
n(CO2)小于等于0.4mol 大于0.2mol
C2H50H+ 3O2=2CO2+ 3H20
0.1~0.2mol 0.2~0.4 mol
n(C2H5OH)介于0.1mol与0.2mol
当n(C2H5OH)=1 Mol 时
放出5～10Q热量（包括5Q）
所以选D

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