=5^1÷5^log0.2(3)=5÷0.2^-log0.2(3)=5÷0.2^log0.2(3^-1)=5÷0.2^log0.2(1/3)=5÷1/3=15换底公式=(lg3/lg4)(lg2/lg9)-lg32^(1/4)/lg(1/2)=(lg3/2lg2)(lg2/2lg3)-lg2^(5/4)/(-lg2)=(1/2*1/2)(lg3/lg2)(lg2/lg3)+(5/4)lg2/lg2=1/4+5/4=3/2