5的1-(log0.2为底3为真数)次幂=? (log4为底3为真数)*(log9为底2为真数)-(log1⼀2为底4次根号下32=

过程
2024-12-16 18:25:30
推荐回答(1个)
回答1:

=5^1÷5^log0.2(3)
=5÷0.2^-log0.2(3)
=5÷0.2^log0.2(3^-1)
=5÷0.2^log0.2(1/3)
=5÷1/3
=15

换底公式
=(lg3/lg4)(lg2/lg9)-lg32^(1/4)/lg(1/2)
=(lg3/2lg2)(lg2/2lg3)-lg2^(5/4)/(-lg2)
=(1/2*1/2)(lg3/lg2)(lg2/lg3)+(5/4)lg2/lg2
=1/4+5/4
=3/2