1-2/(x-2)<-32/(x-3)>40<(x-3)/2<1/4031<1-2/(x-2)<2-1<2/(x-2)<0所以(x-2)/2<-1x-2<-2x<0所以定义域(-无穷,0)∪(3,7/2)
=(40-3/4)×(40+3/4)=40²-(3/4)²=1600-9/16=1599+7/16=1599又16分之7
