已知x^2+2x-1=0,求x^3-5x+3的值?

2024-12-26 18:16:56
推荐回答(1个)
回答1:

错了吧,是求2x³-5x+3?

x²+2x-1=0
x²=-2x+1
以下x²都有-2x+1代替
则x³=x(x²)
=x(-2x+1)
=-2x²+x
=-2(-2x+1)+x
=5x-2

所以原式=(5x-2)-5x+3
=5x-2-5x+3
=1