不定积分∫1⼀(x^2(1+x^2))dx, 求解

2024-12-15 10:57:28
推荐回答(1个)
回答1:

∫1/(x^2(1+x^2))dx = ∫[(1+x^2)-x^2]/(x^2(1+x^2))dx = ∫[1/x^2-1/(1+x^2)]dx
=∫1/x^2dx - ∫1/(1+x^2)dx = -1/x -arctan x + C