数学题目:化简1⼀(2!)+2⼀(3!)+3⼀(4!)……(n-1)⼀(n!)

2024-12-15 09:13:39
推荐回答(1个)
回答1:

解:原式=[1/(2-1)!-1/(2!)]+[1/(3-1)!-1/3!]+……+[1/(n-1)!-1/n!]
=1/1!-1/2!+1/2!-1/3!+......+1/(n-1)!-1/n!
=1-1/n!
=(n!-1)/n!