2. 范德蒙行列式展开为 f(x) = (2-1)(3-1)...(n-1-1)(x-1)(3-2)(4-2)...(n-1-2)(x-2)......(x-n+1) = 0, 得 x = 1, 2, ..., n-1
1到n-1
我怎么知道
