问题 若(x-1)(y+1)=3 xy(x-y)=4 求x的7次方-y的7次方的值 谢谢诶

2024-12-26 22:14:02
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回答1:

(x-1)(y+1)=3 即xy+x-y=4
又xy(x-y)=4
所以 xy=x-y=2 y^2+2y+1=3
y=-1+3^(1/2) y=-1-3^(1/2)
x=1+3^(1/2) x=1-3^(1/2)
x的7次方+y的7次方=(-1+3^(1/2))^7+(1+3^(1/2))^7
=(-1-3^(1/2))^7+(1-3^(1/2))^2