(2x+y)(2x-3y)+x(2x+y) 因式分解

8^2(2x^2-y^2)+y^4 3x^2-27
2025-01-02 07:59:24
推荐回答(4个)
回答1:

(2x+y)(2x-3y)+x(2x+y)
=(2x+y)(2x-3y+x)
=(2x+y)(3x-3y)
=3(2x+y)(x-y)
8^2(2x^2-y^2)+y^4
=64(2x^2-2y^2)+y^4+64y^2
=128(x^2-y^2)+y^2(y^2+64)
=128(x+y)(x-y)+y^2(y^2+64) ????????
3x^2-27
=3(x^2-9)
=3(x+3)(x-3)

回答2:

1、原式=(2X+Y)(2X-3Y+X)=3(2X+Y)(X+Y)
2、是不是题有问题
3、原式=3(x^2-9)=3(X-9)(X+9)

回答3:

(2x+y)(2x-3y)+x(2x+y)
=(2x+y)(2x-3y+x)
=(2x+y)(3x-3y)
=3(2x+y)(x-y)

3x^2-27
=3(x^2-9)
=3(x+3)(x-3)

回答4:

(2x+y)(2x-3y)+x(2x+y)
=(2x+y)(2x-3y+x)
=3(2x+y)(x-y)

8^2(2x^2-y^2)+y^4=64(2x^2-y^2)+y^4
=64*2(x^2-y^2)+64y^2+y^4
=128(x+y)(x-y)+y^2(64+y^2)

3x^2-27 =3(x^2-9)=3(x-3)(x+3)