x²=3x+1
则x²用3x+1代替
x³=x×x²
=x(3x+1)
=3x²+x
=3(3x+1)+x
=10x+3
原式=3(10x+3)-11(3x+1)+3x+2
=30x+9-33x-11+3x+2
=0
因为x^2-1=3x
3x^3-11x^2+3x+2
=3x(x^2-1)-11x^2+6x+2
=9x^2-11x^2+6x+2
=-2x^2+2(x^2-1)+2
=0
x^2-3x-1=0
3x^3-11x^2-3x-2=3(x^2-3x-1)-2(x^2-3x-1)=0
545