推荐回答（5个）
抽到一张特定牌的概率就是特定牌的张数除以54，然后化简。
比如抽到大王的概率是1/54.抽到6的概率是4/54.
抽到两张特定牌的概率是两张概率之积。
比如：抽到大王和6的概率是1/54*4/53.
三张是一样，一直往下乘。
比如抽到方块6、黑桃5和一张A的概率是多少？1/54*1/53/4/52.
这里为什么第二次抽时数会变小，因为你是连续抽，第一张抽出后，便不在放回牌里，所以，第二次抽时总共只有53张牌了。依次类推。
抽四张牌的组合数有C(54,4)种。
包含特定一张牌，就是说剩下的53张再取三张，组合数为C(53,3)。这样概率就是C(53,3)/C(54,4)=4/54.
包含两张牌就是说剩下52张再随便找两张，组合数为C(52,2)。这样概率就是C(52,2)/C(54,4)=4/54 * 3/53.
三张以此类推，四张就是只有唯一一种情况，所以概率是1/C(54,4).
一副扑克共54张牌，抽出四张为54C4=316251.一张已知的必须抽出抽出其他3张为53C3=23426.所以概率0.074，依此类推
要看你的牌你面包不包括王了,我这里假设不包括就是52张牌
有1张6的概率: 4/52=1/13
包括2张特定牌就要分是特定颜色还是特定牌上的值
特定颜色: 有4中颜色每种13个,那就是先选13/52 然后 12/51
所以就是 13*12/(52*51)=1/17
特定值 : 4/52*3/51=1/221
三个,四个是一样的道理,往上乘就行了
设为52张,每次抽4张的组合数为C(52 4)=270725,有一张特定牌的组合数为
C(48 3)=17296.
其中有一张的概率是4*C(48 3)/C(52 4)=17296*4/270725=0.256 (有四种花色需乘4)
同样算法:有两张的概率是C(4 2)*C(48 2)/C(52 4)
有三张的概率是C(4 3)*C(48 1)/C(52 4)
有四张的概率是1/270725
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