求达人帮忙看看,这道题该怎么做,要有过程哦,谢谢

2025-01-24 05:27:44
推荐回答(1个)
回答1:

lim(x→π)sinmx/sinnx
x=π-t
lim(x→π)sinmx/sinnx=lim(t→0)sinm(π-t)/sinn(π-t)=lim(t→0)[-mcos(m(π-t))]/[-ncosn(π-t)]
m和n同时为奇数或同时为偶数时,
lim(x→π)sinmx/sinnx=m/n
m为奇数n为偶数,或者m为偶数n为奇数时,
lim(x→π)sinmx/sinnx=-m/n