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求函数的微分dy
2025-01-02 18:08:11
推荐回答(2个)
回答1:

回答2:

(3)
y=(2x+3)(x-6)^(1/4)/ (x+1)^(1/3)
lny =ln(2x+3)+(1/4)ln(x-6)-(1/3)ln(x+1)
dy/y ={ 2/(2x+3)+(1/4)[1/(x-6)]-(1/3)[1/(x+1)] } dx
dy ={ 2/(2x+3)+(1/4)[1/(x-6)]-(1/3)[1/(x+1)] } . [(2x+3)(x-6)^(1/4)/ (x+1)^(1/3) ]dx
(4)
xy = a^2
xdy +ydx = 0
dy = -(y/x) dx