怎么判断某种盐的水溶液究竟是显酸性还是碱性还是中性?

2024-12-21 10:02:11
推荐回答(5个)
回答1:

首先要知道,水极微弱电离为H+,OH-,
弱酸酸根,如CO3 2-,与水中H+结合,平衡偏向于OH-,溶液成碱性。
硫酸氢根,其盐溶液能够在水中电离出H+,所以成酸性。提示一点,HCO3 -在水中无法继续电离,所以不呈酸性,而且HCO3 -为弱酸酸根,平衡反而向OH-移动,导致溶液成碱性。
金属离子方面,如果其碱(如Al,对应的碱为Al(OH)3)为难溶(这个应该会判断吧),那么水中的电离平衡向H+移动,故溶液成酸性。
如果不具备以上2点,则成中性,如Na2SO4

对于你的第二个问题:
给你一个参考的吧,高中常用的
强酸:HCl,H2SO4,HNO3,HClO3,HClO4(无机酸中的最强酸),H2S2O7(焦硫酸)
HBrO3,HBrO4,HIO4,HBr,HI,高浓度的HF,H2SeO4,CF3COOH
弱酸就很多了:H3BO3,H2CO3,H2SiO3,H4SiO4,H2Se,H2Te,CH3COOH
剩下的基本上都是中强酸了……

希望采纳,谢谢

回答2:

先说酸的强弱之分吧。
酸有两个理论定义。一个是酸碱质子论,一个是酸碱电子论。一般来说第一个比较常用。定义是这样的:一种物质能够提供质子(氢离子),就是酸,一个物质能够接受质子就是碱。而且这个东西是相对而言的,一个物质能在另一个物质中质子化,就是碱,而提供质子的物质就是酸。比如说一种名叫魔酸的超酸,能使浓硫酸在里面质子化,那么浓硫酸的酸性就比它弱,并且显碱性了。
也就是说提供氢离子的能力越强,酸性越强。
盐溶液的酸碱是由于水解造成的,因为水能够微弱的电离出氢离子和氢氧根离子。而如果一个盐是由弱酸根和强碱对应的阳离子构成的话,弱酸根结合了氢离子形成了难电离的弱酸,而这个阳离子是很难结合氢氧根离子话,就使溶液中的氢氧根浓度偏大,溶液显碱性。
显酸性的话就倒过来。
一个盐显酸性,就使由强酸对应的阴离子和弱碱对应的阳离子构成。碱性的话,就使由强碱对应的阳离子和弱酸对应的阴离子构成。强酸强碱盐显中性。弱酸弱碱盐一般都发生双水解反应而不能稳定存在,如果不能反应彻底的话,弱酸弱碱盐的酸碱性就只能根据实验数据或是电离常数来判断了。
各举一个列子:
酸性盐:FeCl3
碱性盐:Na2CO3.
中性盐:NaCl
极易双水解的盐:AL2S3。
不易双水解的弱酸弱碱盐:NH4HCO3.

回答3:

强酸强碱的盐呈中性,弱酸强碱盐显碱性(酸根吸收氢离子,会使溶液里氢氧根增多),强酸弱碱盐显酸性(金属离子吸收氢氧根离子,使溶液里氢离子增多)。
对弱酸弱碱盐,理论上可以通过某些物理数值估算一下,但在高中阶段不会要求。最好的检验方法当然是配成溶液然后测定pH

回答4:

周期表IA,IIA元素阳离子可能是强碱,其他阳离子可认为都是弱碱,VA,VIA,VIIA元素阴离子可能是强酸,其他阴离子可认为都是弱酸。强酸强碱盐=中性;强碱弱酸盐=碱性,弱碱强酸盐=酸性,弱酸弱碱盐和水反应。酸碱盐的结构:阳离子+【OH-】=碱,阴离子+【H+】=酸,阴离子+阳离子=盐

回答5:

强酸弱碱盐溶于水显酸性
如al2(so4)3溶于水后,al3+会发生如下水解反应
al3+
+3h2o
=
al(oh)3
+
3h+
你可以发现水解后得到了h+,说明溶液是酸性的
强碱弱酸盐溶于水一般显碱性
如na2s溶于水发生如下水解反应
s2-
+
h2o
=
hs
-
+
oh-
hs-
+
h2o
=
h2s
+
oh-
强酸强碱盐一般是中性的,如氯化钠
弱酸弱碱盐一般发生双水解
al2s3+6h2o=2al(oh)3+3h2s

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