(1-a눀)(1-b눀)-(a눀-1)눀(b눀-1)눀

2025-01-01 18:51:40
推荐回答(2个)
回答1:

(1-a²)(1-b²)-(a²-1)²(b²-1)²
=(1-a)*(1+a)*(1-b)*(1+b)-
(1-a)*(1+a)*(1-b)*(1+b)*(1-a)*(1+a)*(1-b)*(1+b)
=(1-a²)(1-b²)*[1-(1-a²)(1-b²)]=(1-a²)(1-b²)*(a²+b²-a²*b²)

回答2:

(1-a²)(1-b²)-(a²-1)²(b²-1)²
=(a²-1)(b²-1)-(a²-1)²(b²-1)²
=(a²-1)(b²-1)[1-(a²-1)(b²-1)]
=(a²-1)(b²-1)(1-a²b²+a²+b²-1)
=(a²-1)(b²-1)(-a²b²+a²+b²)
=(a+1)(a-1)(b+1)(b-1)(a²+b²-a²b²)