只用 1、2、3三个数字组成一个四位数,规定这三个数必须同时使用?
推荐回答(3个)
若有两个1
则他们在13,14或24位
其他两位是2和3
可以颠倒
则1在13位有两个
14和24为也是两个
所以有两个1时有3×2=6个
则两个2或两个3式也是6个
所以一共6×3=18个
1231
1232
1212
1213
1312
1321
1313
1323
2121
2131
2132
2123
2312
2321
2313
2323
3123
3121
3131
3132
3212
3213
3231
3232
你算重复了
比如
123,你再加1个1
比如1213
这和213,再加1个1
也可以得到1213
所以你这样每个数都算了两次
所以还要除以2
1231
1232
1212
1213
1312
1321
1313
1323
2121
2131
2132
2123
2312
2321
2313
2323
3123
3121
3131
3132
3212
3213
3231
3232
三个数必须同时使用
18个
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