解方程:(x-4)⼀(x-5)-(x-5)⼀(x-6)=(x-7)⼀(x-8)-(x-8)⼀(x-9)

2025-02-03 00:04:07
推荐回答(1个)
回答1:

(x-4)/(x-5) - (x-5)/(x-6) = (x-7)/(x-8) - (x-8)/(x-9)

(x-5+1)/(x-5) - (x-6+1)/(x-6) = (x-8+1)/(x-8) - (x-9+1)/(x-9)

1+1/(x-5)-1-1/(x-6) = 1+1/(x-8)-1-1/(x-9)

1/(x-5)-1/(x-6) = 1/(x-8)-1/(x-9)

(x-6-x+5)/{(x-5)(x-6)} = (x-9-x+8)/{(x-8)(x-9)

-1/{(x-5)(x-6)} = -1/{(x-8)(x-9)

(x-5)(x-6) = (x-8)(x-9)

x²-11x+30 = x²-17x+72

-11x+17x = 72-30

6x = 42

x = 7

将检验,x=7是原方程的解。