求y=(sinx-xcosx)⼀(cosx+xsinx)的导数

2025-01-25 06:57:49
推荐回答(1个)
回答1:

(sinx-xcosx)'=(sinx)’-(xcosx)’ =cosx-x'*cosx-x*(cosx)' =cosx-cosx+xsinx =xsinx (cosx+xsinx)’=(cosx)’+(xsinx)’=-sinx+x'*sinx+x*(sinx)’=-sinx+sinx+xcosx=xcosx