数列1,2+1⼀2,3+1⼀2+1⼀4.....n+1⼀2+1⼀4....+1⼀2^n-1 的前n项和为

数列1,2+1/2,3+1/2+1/4.....n+1/2+1/4....+1/2^n-1 的前n项和为谢谢了
2024-12-28 17:27:25
推荐回答(1个)
回答1:

1+2+1/2+3+1/2+1/4........+1/2^n-1

=1+2+3+...+n+1/2+1/4+1/8+.....+1/2^n-1
=(1+n)n/2+1/2*(1-1/2^n)/(1-1/2)
=(1+n)n/2+1/2*(1-1/2^n)*2
=(1+n)n/2+1-1/2^n