分解因式(x-2)(x-4)(x-6)(x-8)+16= 讲解一下过程,O(∩_∩)O谢谢

2025-02-02 11:09:55
推荐回答(1个)
回答1:

原式=[(x-2)(x-8)][(x-4)(x-6)]+16
=[(x²-10x)+16][(x²-10x)+24]+16
=(x²-10x)²+40(x²-10x)+384+16
=(x²-10x)²+40(x²-10x)+400
=(x²-10x+20)²